(a) 28.28 cos (50001-45°)
(b) 28.28 cos (5000/+ 45°)
(c) 28.28 sin (5000/-45°)
(d) 28.28 sin (5000/+ 45°)
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First find the capacitive reactance
Give in current equation omega(w) =5000
XL=1/Cw = 1/5000*20*10^-6 = 10 ohm
Resistance=10ohm capacitive reactance =10ohms
Now find total impedance
Z = √(10)2^+(10)^2 = 14.14
Now:
V=IZ 2cos5000t*14.14 = 28.28cos(5000t-45)
-45 is because the voltage lags in capacitor.
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